For the last two weeks I am addicted to The Code. Those, who successfully passed pre-selection, were offered to download a PDF file (you need the passwords from the pre-selection to open it) with even more puzzles.

Here is another one I liked:

*A Mathematician's Apology
ABC = A ^{3} + B^{3} + C^{3}
CDE = C^{3} + D^{3} + E^{3}
CDA = C^{3} + D^{3} + A^{3}
FED = F^{3} + E^{3} + D^{3}
A⋅100 + A⋅10 + D = ?*

Now, if you Google for "A Mathematician's Apology", you will come to the following link, which is a book with the same title by Hardy. Section 15 reveals all the solutions for the equation:

* x⋅100 + y⋅10 + z = x ^{3} + y^{3} + z^{3}*

where x∈{1..9}, y,z∈{0..9}. They are (1,5,3), (3,7,0), (3,7,1) and (4,0,7).

The pattern is easy to spot now:

*(A,B,C) = (1,5,3)
(C,D,E) = (3,7,0)
(C,D,A) = (3,7,1)
(F,E,D) = (4,0,7)*

and

*A⋅100 + A⋅10 + D = 117*

However, if (like me) "Google search" isn't (always) an obvious option, the following Java code:

```
public class Code {
public static int func(int a, int b, int c) {
return a*100 + b*10 + c - a*a*a - b*b*b - c*c*c;
}
public static void main(String[] args) {
for (int a = 1; a < 10; a++) {
for (int b = 0; b < 10; b++) {
for (int c = 0; c < 10; c++) {
if (func(a,b,c) == 0) {
System.out.println("("+a+","+b+","+c+")");
}
}
}
}
}
}
```

will also return (1,5,3), (3,7,0), (3,7,1) and (4,0,7).